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Szia Zoli!
Most az =E1ltalad linkelt k=E9pre h=FAztam r=E1 a kontrasztot =FAgy mint =
arra, amit nemr=E9g
a saj=E1t (el=F5bb mell=E9kelt) k=E9pemmel tettem.
Most mell=E9kelem a Te k=E9pedet kontrasztozva. A s=F6t=E9t r=E9sz =
szinte elt=FBnik, a=20
h=E1tt=E9r gradiense sz=E9pen l=E1tszik.
Ern=F5
----- Original Message -----=20
From: Baranyi Zolt=E1n=20
To: =C9szlel=F5 amat=F5rcsillag=E1szok f=F3ruma=20
Sent: Tuesday, April 16, 2013 2:39 PM
Subject: Re: [Leonidak] C2011 L4
Szia Ern=F5!=20
=20
Az =E1ltalam mutatott 13.-i k=E9peken (amit a kiskun list=E1ra =
feltettem) SEMMILYEN, NEM LINE=C1LIS manipul=E1ci=F3 nem t=F6rt=E9nt (se =
asinh,se gradiens levon=E1s,se dekonvul=EDci=F3). Csak dark levon=E1s, =
csillagra majd =FCstire igaz=EDt=E1s =E9s =F6sszegz=E9s.
A s=F6t=E9t r=E9sz -az =E9n gyenge k=E9pimen!- nagy =E1tlagban 20 =
=E9rt=E9kkel kevesebb a k=F6rnyezet=E9n=E9l (3400 k=F6r=FCli alaphoz =
m=E9rten) akkor,amikor a cs=FAcs feh=E9r 37000! Ez majdnem 1/2000 =
r=E9sz. azt 8 bites (255 l=E9pcs=F5s felbont=E1sba ) megmutatni csak =
=FAgy lehet,ha durv=E1n =E1tsk=E1l=E1zzuk a k=E9pet.De ez n=E1lam =
line=E1lis. Ezzel a m=FBterm=E9ket el is vethetj=FCk..=20
=20
Az=E9rt k=F6sz=F6n=F6m,hogy ut=E1nan=E9zt=E9l a dolognak! J
=20
Az=E9rt a vide=F3kat =E9rdemes megn=E9ni!
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Szia Zoli!
Most az =E1ltalad linkelt k=E9pre =
h=FAztam r=E1 a=20
kontrasztot =FAgy mint arra, amit nemr=E9g
a saj=E1t (el=F5bb mell=E9kelt) =
k=E9pemmel=20
tettem.
Most mell=E9kelem a Te k=E9pedet =
kontrasztozva. A s=F6t=E9t=20
r=E9sz szinte elt=FBnik, a
h=E1tt=E9r gradiense sz=E9pen =
l=E1tszik.
Ern=F5
style=3D"PADDING-RIGHT: 0px; PADDING-LEFT: 5px; MARGIN-LEFT: 5px; =
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----- Original Message -----
style=3D"BACKGROUND: #e4e4e4; FONT: 10pt arial; font-color: =
black">From:=20
Baranyi =
Zolt=E1n=20
style=3D"FONT-SIZE: 11pt; COLOR: #1f497d; FONT-FAMILY: =
´Calibri´,´sans-serif´">Szia=20
Ern=F5!
style=3D"FONT-SIZE: 11pt; COLOR: #1f497d; FONT-FAMILY: =
´Calibri´,´sans-serif´">
style=3D"FONT-SIZE: 11pt; COLOR: #1f497d; FONT-FAMILY: =
´Calibri´,´sans-serif´">Az=20
=E1ltalam mutatott 13.-i k=E9peken (amit a kiskun list=E1ra feltettem) =
SEMMILYEN,=20
NEM LINE=C1LIS manipul=E1ci=F3 nem t=F6rt=E9nt (se asinh,se gradiens =
levon=E1s,se=20
dekonvul=EDci=F3). Csak dark levon=E1s, csillagra majd =FCstire =
igaz=EDt=E1s =E9s=20
=F6sszegz=E9s.
style=3D"FONT-SIZE: 11pt; COLOR: #1f497d; FONT-FAMILY: =
´Calibri´,´sans-serif´">A=20
s=F6t=E9t r=E9sz –az =E9n gyenge k=E9pimen!- nagy =E1tlagban 20 =
=E9rt=E9kkel kevesebb a=20
k=F6rnyezet=E9n=E9l (3400 k=F6r=FCli alaphoz m=E9rten) akkor,amikor a =
cs=FAcs feh=E9r 37000!=20
Ez majdnem 1/2000 r=E9sz. azt 8 bites (255 l=E9pcs=F5s felbont=E1sba ) =
megmutatni csak=20
=FAgy lehet,ha durv=E1n =E1tsk=E1l=E1zzuk a k=E9pet.De ez n=E1lam =
line=E1lis. Ezzel a=20
m=FBterm=E9ket el is vethetj=FCk….
style=3D"FONT-SIZE: 11pt; COLOR: #1f497d; FONT-FAMILY: =
´Calibri´,´sans-serif´">
style=3D"FONT-SIZE: 11pt; COLOR: #1f497d; FONT-FAMILY: =
´Calibri´,´sans-serif´">Az=E9rt=20
k=F6sz=F6n=F6m,hogy ut=E1nan=E9zt=E9l a dolognak!
style=3D"FONT-SIZE: 11pt; COLOR: #1f497d; FONT-FAMILY: =
Wingdings">J
style=3D"FONT-SIZE: 11pt; COLOR: #1f497d; FONT-FAMILY: =
´Calibri´,´sans-serif´">
style=3D"FONT-SIZE: 11pt; COLOR: #1f497d; FONT-FAMILY: =
´Calibri´,´sans-serif´">
style=3D"FONT-SIZE: 11pt; COLOR: #1f497d; FONT-FAMILY: =
´Calibri´,´sans-serif´">Az=E9rt=20
a vide=F3kat =E9rdemes =
megn=E9ni!